Solved Examples/Numericals On Coordinate System & Transformation - 2.
Q.7 Calculate the distance between the following pair of points?
a) (2, 1, 5) and (6, -1, 2)
b) (3, π/2, -1) and (5, 3π/2, 5)
c) (10, π/4, 3π/4) and (5, π/6, 7π/4)
Ans. a) Distance between two points in Cartesian co-ordinate is given as:
d2 = (x2 – x1) 2 +(y2 – y1) 2 +(z2 – z1) 2
= (6 – 2) 2 + (-1 -1) 2 + (2 – 5) 2
= (29) 1/2 => d = 5.38
b) Distance between two points in cylindrical co-ordinate system is given as:
d2 = ρ22 + ρ12 - 2ρ1ρ2 cos(φ2 – φ1) + (z2 – z1) 2
= 52 + 32 – 2.5.3 cos(3π/2 - π/2) + (5 +1) 2
= (100) 1/2 =>d = 10.
c) Distance between two points in spherical co-ordinate system is given as:
d2 = r22 + r12 – 2r1r2 cosθ2 cosθ1 + 2r1 r2 sinθ2 sinθ1 cos(φ2 – φ1)
= 102 + 52 – 2.5.10 cosπ/4 cosπ/6 + 2.5.10 sinπ/4 sinπ/6 cos(7π/4 - 3π/4)
= (99.12) 1/2 => d = 9.96
Q.8 Find the distance between A (2, π /6, 0) and B = (1, π /2, 2) ?
Ans:
The points are given in Cylindrical Co-ordinate (ρ, φ, z). To find the distance between two points, the co-ordinates are to be in Cartesian (rectangular). The corresponding rectangular co-ordinates are (ρ Cosφ, ρ Sinφ, z).
Position vector of A:
rA = x ax + y ay + z az
= ρ Cosφ ax + ρ Sinφ ay + z az
= 2cos φ/6 ax + 2 Sinφ/6 ay
= 1.73 ax + ay
Similarly,
Position vector of B:
rB = ρ Cosφ ax + ρ Sinφ ay + z az
= 1 Cosφ/2 ax + 1 Sinφ/2 ay + 2az
= ay + 2az
Distance Vector rAB = rB – rA = - 1.73 ax + 2az
Hence the distance between the two points is given as :
| rAB | = 2.64
Q.9 Using the differential length dl, for the length of each of the following curves:
a) ρ = 3, π /4 < φ < π /2, z = constant.
Ans:
dl = ρ dφ
L = ∫dl = 3∫π /4π /2 dφ = 3 ( π /2 – π /4) = 3π /4 = 2.356
b) r = 1, θ = 30o, 0o < φ < 60o
Ans:
dl = rsinθ dφ
L = ∫dl = rsinθ∫0π /3 dφ = (1) sin 30o [ π /3 – 0] = 0.5236
c) r = 4, φ = constant, 30o < θ < 90o
Ans:
dl = rdθ
L = ∫dl = r∫π /6π /2dθ = 4 [ π /2 – π /6] = 4π /3 = 4.189
Q.10 Calculate the areas of the following surfaces using the differential surface area ds:
a) ρ = 2, π/3 < φ < π/2, 0 < z < 5.
Ans:
ds = ρ dφ dz
S = ∫ds = ∫ ∫ ρ dφ dz = 2 ∫π/3π/2 dφ ∫05 dz = 2 (5) [π/2 – π/3] = 10π/6 = 5.236
b) r = 10, π/4 < θ < 2π/3 , 0 < φ < 2π
Ans:
ds = r2sinθ dθdφ
S = ∫ds = ∫ ∫ r2sinθ dθdφ = 102 ∫π/42π/3sinθdθ ∫02πdφ = 100(2π) |(-cosθ)|π/42π/3 = 7.584
Q.11 Use the differential volume dv to determine the volumes of the following regions:
a) 0 < x < 1, 1 < y <2, -3 < z < 3
Ans:
dv = dx dy dz
V = ∫ ∫ ∫ dx dy dz = ∫01dx ∫12dy ∫-33dz = (1) (2 - 1)(3 +3) = 6
b) 2 < ρ < 5, π/3 < φ < π, - 1 < z < 4
dv = ρ dρ dφ dz
V = ∫ ∫ ∫ ρ dρ dφ dz = ∫25ρdρ ∫π/3π dφ ∫-14 dz = | ρ2 /2 |25 (π – π /3) (4 + 1) = 35 π = 110
ALSO READ:
- Introduction To Coordinate System.
- Cartesian Coordinate System / Rectangular Coordinate System (x, y, z).
- Differential Analysis Of Cartesian Coordinate System.
- Circular Cylindrical Coordinate System (ρ, φ, z).
- Differential Analysis Of Cylindrical Coordinate System.
- Spherical Coordinate System ( r, θ , φ).
- Differential Analysis Of Spherical Coordinate System.
- Numericals / Solved Examples - Page 1.
- Numericals / Solved Examples - Page 2.
Your suggestions and comments are welcome in this section. If you want to share something or if you have some stuff of your own, please do post them in the comments section.
a) (2, 1, 5) and (6, -1, 2)
b) (3, π/2, -1) and (5, 3π/2, 5)
c) (10, π/4, 3π/4) and (5, π/6, 7π/4)
Ans. a) Distance between two points in Cartesian co-ordinate is given as:
d2 = (x2 – x1) 2 +(y2 – y1) 2 +(z2 – z1) 2
= (6 – 2) 2 + (-1 -1) 2 + (2 – 5) 2
= (29) 1/2 => d = 5.38
b) Distance between two points in cylindrical co-ordinate system is given as:
d2 = ρ22 + ρ12 - 2ρ1ρ2 cos(φ2 – φ1) + (z2 – z1) 2
= 52 + 32 – 2.5.3 cos(3π/2 - π/2) + (5 +1) 2
= (100) 1/2 =>d = 10.
c) Distance between two points in spherical co-ordinate system is given as:
d2 = r22 + r12 – 2r1r2 cosθ2 cosθ1 + 2r1 r2 sinθ2 sinθ1 cos(φ2 – φ1)
= 102 + 52 – 2.5.10 cosπ/4 cosπ/6 + 2.5.10 sinπ/4 sinπ/6 cos(7π/4 - 3π/4)
= (99.12) 1/2 => d = 9.96
Q.8 Find the distance between A (2, π /6, 0) and B = (1, π /2, 2) ?
Ans:
The points are given in Cylindrical Co-ordinate (ρ, φ, z). To find the distance between two points, the co-ordinates are to be in Cartesian (rectangular). The corresponding rectangular co-ordinates are (ρ Cosφ, ρ Sinφ, z).
Position vector of A:
rA = x ax + y ay + z az
= ρ Cosφ ax + ρ Sinφ ay + z az
= 2cos φ/6 ax + 2 Sinφ/6 ay
= 1.73 ax + ay
Similarly,
Position vector of B:
rB = ρ Cosφ ax + ρ Sinφ ay + z az
= 1 Cosφ/2 ax + 1 Sinφ/2 ay + 2az
= ay + 2az
Distance Vector rAB = rB – rA = - 1.73 ax + 2az
Hence the distance between the two points is given as :
| rAB | = 2.64
Q.9 Using the differential length dl, for the length of each of the following curves:
a) ρ = 3, π /4 < φ < π /2, z = constant.
Ans:
dl = ρ dφ
L = ∫dl = 3∫π /4π /2 dφ = 3 ( π /2 – π /4) = 3π /4 = 2.356
b) r = 1, θ = 30o, 0o < φ < 60o
Ans:
dl = rsinθ dφ
L = ∫dl = rsinθ∫0π /3 dφ = (1) sin 30o [ π /3 – 0] = 0.5236
c) r = 4, φ = constant, 30o < θ < 90o
Ans:
dl = rdθ
L = ∫dl = r∫π /6π /2dθ = 4 [ π /2 – π /6] = 4π /3 = 4.189
Q.10 Calculate the areas of the following surfaces using the differential surface area ds:
a) ρ = 2, π/3 < φ < π/2, 0 < z < 5.
Ans:
ds = ρ dφ dz
S = ∫ds = ∫ ∫ ρ dφ dz = 2 ∫π/3π/2 dφ ∫05 dz = 2 (5) [π/2 – π/3] = 10π/6 = 5.236
b) r = 10, π/4 < θ < 2π/3 , 0 < φ < 2π
Ans:
ds = r2sinθ dθdφ
S = ∫ds = ∫ ∫ r2sinθ dθdφ = 102 ∫π/42π/3sinθdθ ∫02πdφ = 100(2π) |(-cosθ)|π/42π/3 = 7.584
Q.11 Use the differential volume dv to determine the volumes of the following regions:
a) 0 < x < 1, 1 < y <2, -3 < z < 3
Ans:
dv = dx dy dz
V = ∫ ∫ ∫ dx dy dz = ∫01dx ∫12dy ∫-33dz = (1) (2 - 1)(3 +3) = 6
b) 2 < ρ < 5, π/3 < φ < π, - 1 < z < 4
dv = ρ dρ dφ dz
V = ∫ ∫ ∫ ρ dρ dφ dz = ∫25ρdρ ∫π/3π dφ ∫-14 dz = | ρ2 /2 |25 (π – π /3) (4 + 1) = 35 π = 110
ALSO READ:
- Introduction To Coordinate System.
- Cartesian Coordinate System / Rectangular Coordinate System (x, y, z).
- Differential Analysis Of Cartesian Coordinate System.
- Circular Cylindrical Coordinate System (ρ, φ, z).
- Differential Analysis Of Cylindrical Coordinate System.
- Spherical Coordinate System ( r, θ , φ).
- Differential Analysis Of Spherical Coordinate System.
- Numericals / Solved Examples - Page 1.
- Numericals / Solved Examples - Page 2.
Your suggestions and comments are welcome in this section. If you want to share something or if you have some stuff of your own, please do post them in the comments section.
Nice work man... Thanks a lot..
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