Solved Exercise/Numericals - Electric Field Intensity (E) - Line, Surface & Mixed Charge Configuration - 2.
Q.1 An infinite long uniform line charge is located at y = 3, z = 5. If ρ L = 30 nC/m. Calculate the electric field at point (5, 6, 1). Ans: The electric field intensity (E) due to an infinite line charge is given as: In this case, ρ = (6 – 3) a y + ρ(1 – 5)a z = 3a y – 4a z Hence a ρ = (3a y - 4a z ) / 5 Therefore E is, Q.2 A uniform line charge density 20 nC lies on z axis between z = 1 and z = 3. Find electric field intensity at point (4, 0, 0). Ans: Electric field due to a line charge density is given as: In this case R = 4 a x – z a z a r = (4 a x – z a z ) / (4 2 + z 2 ) Hence we have, Q. 3 Two identical charges are located on the y axis at y = 3 and y = 9. At what point in space is the net electric field zero? Ans: As the both charges are on the y axis, the point at which the fields due to the two charges can cancel has to lie on the y-axis also. Since the two charges are identical, the point at whi...