Solved Exercise/Numericals - Electric Field Intensity (E) & Force (F) - 1.
Q.1 Point charges Q1 = 5 μC and Q2 = -4 μC are placed at (3, 2, 1) and (-4, 0, 6) respectively. Determine the force on Q1.
Ans:
Force on Q1 due to Q2 is given as :
= -5.74 ax – 1.642 ay + 4.104 az mN
Q. 2 Five Identical 15 μC point charges are located at the center and corners of a square defined by -1 < x, y > 1 and z = 0.
Find the force on the 10 μC point charge at (0, 0, 2).
Therefore,
F / 1.35 = [(0, 0, 2) / 8] + [(-1, -1, 2) / 63/2] + [(1, -1, 2) / 63/2]
+ [(-1, 1, 2) / 63/2] + [(1, 1, 2) / 63/2]
→ F = 1.35 [(0.25 + (8 / 63/2)] az
= 1.072az N
Q.3 Point Charges Q1 and Q2 are respectively located at (4, 0, -3) and (2, 0, 1). If Q2 = 4nC, find Q1 such that
a) The E at (5, 0, 6) has no z component.
b) The force on a test charge at (5, 0, 6) has no x component.
a) Electric field intensity at point (5, 0, 6) is given as:
Hence Q1 = - 3.463 nC.
b) F (5, 0, 6) = qE (5, 0, 6)
If Ex = 0
Hence, Q1 = -18.7 nC.
Q. 4 Determine the total charge
a) On line 0 < x < 5 m if ρL = 2x2 mC/m
Ans:
Q = ∫L ρl dl
= ∫05 (2 x2)dx
= | 4x3 |05 = 0.5 C
b) On the cylinder ρ = 3, 0 < z < 4, if ρs = ρz2 nC/m2∫S ρsds = ∫S ρz2 ds
= ∫S ρz2 (ρ dφ dz)
= ∫(φ =0)2π ∫(z =0)4 ρz2 (ρ dφ dz)
= (ρ3 / 3) (2π) | z3 / 3 |04
= 9 x (2π) x (43 / 3)
= 1.206 μC
c) Within the sphere r = 4m, if ρv = 10 / (r sinθ ) C / m3
Ans:
Q = ∫V ρvdv
= ∫V [ 10 / (r sinθ ) ] (r2 sinθ dr dθ dφ)
= ∫(r=0)4 ∫(θ=0)π ∫(φ=0)2π (10 rdr dθ dφ)
= 10 | r2 / 2 |04 (2π) (π)
= 157.91 C
ALSO READ:
- Introduction To Electrostatics.
- Coulomb's law.
- Electric Field Intensity (E).
- Electric Lines Of Forces /Streamlines / Electric Flux (ψ) .
- Electric Flux Density (D).
- Electric Field Intensity Due To a Finite and Infinite Line Charge.
- Electric Field Intensity Due To a Infinite Sheet Charge.
- Electric Field Intensity Due To a Circular Ring Charge.
- Electric Field Intensity Due To a Circular Disk Charge.
- Numericals / Solved Examples - Electric Force and Field Intensity.
- Numericals / Solved Examples - Electric Field Intensity - Line, Surface and Mixed Charge Configuration.
- Short Notes/FAQ's
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just it is nice.
ReplyDeletegood work
ReplyDeleteit's ok
ReplyDeleteFor Q3, shouldn't |(3, 0, 5)| be (34)^3/2 instead of (61)^3/2 ??
ReplyDeletenot bad....
ReplyDelete